y^2-14y+43=0

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Solution for y^2-14y+43=0 equation:


Simplifying
y2 + -14y + 43 = 0

Reorder the terms:
43 + -14y + y2 = 0

Solving
43 + -14y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-43' to each side of the equation.
43 + -14y + -43 + y2 = 0 + -43

Reorder the terms:
43 + -43 + -14y + y2 = 0 + -43

Combine like terms: 43 + -43 = 0
0 + -14y + y2 = 0 + -43
-14y + y2 = 0 + -43

Combine like terms: 0 + -43 = -43
-14y + y2 = -43

The y term is -14y.  Take half its coefficient (-7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
-14y + 49 + y2 = -43 + 49

Reorder the terms:
49 + -14y + y2 = -43 + 49

Combine like terms: -43 + 49 = 6
49 + -14y + y2 = 6

Factor a perfect square on the left side:
(y + -7)(y + -7) = 6

Calculate the square root of the right side: 2.449489743

Break this problem into two subproblems by setting 
(y + -7) equal to 2.449489743 and -2.449489743.

Subproblem 1

y + -7 = 2.449489743 Simplifying y + -7 = 2.449489743 Reorder the terms: -7 + y = 2.449489743 Solving -7 + y = 2.449489743 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + y = 2.449489743 + 7 Combine like terms: -7 + 7 = 0 0 + y = 2.449489743 + 7 y = 2.449489743 + 7 Combine like terms: 2.449489743 + 7 = 9.449489743 y = 9.449489743 Simplifying y = 9.449489743

Subproblem 2

y + -7 = -2.449489743 Simplifying y + -7 = -2.449489743 Reorder the terms: -7 + y = -2.449489743 Solving -7 + y = -2.449489743 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + y = -2.449489743 + 7 Combine like terms: -7 + 7 = 0 0 + y = -2.449489743 + 7 y = -2.449489743 + 7 Combine like terms: -2.449489743 + 7 = 4.550510257 y = 4.550510257 Simplifying y = 4.550510257

Solution

The solution to the problem is based on the solutions from the subproblems. y = {9.449489743, 4.550510257}

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